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In the mixture of NaHCO(3) and NaCO(3), ...

In the mixture of `NaHCO_(3)` and `NaCO_(3)`, volume of a given HCl required is x ml with phenolphathalein indicator and further y mL is required with methyl orange indicator. Hence volume of HCl for complete reaction of `NaHCO_(3)` present in the original mixture is

A

2x

B

y

C

`x//2`

D

`(y-x)`

Text Solution

Verified by Experts

The correct Answer is:
D
In presence of phenolchalein photacium
Eq. o HCl = `(1)/(2)` Eq `NC_(2)CO_(3)`
`XxxN=(1)/(2)` eq `NO_(2)CO_(3)`
In presence of methyl orange
Eq. of `HCl=(1)/(2)` Eq `NO_(2)CO_(3)+` Eq `NaHCO_(3)`
`yxxN=xN+` Eq `NaHCO_(3)`
`therefore` Eq `NaHCO_(3)` = `(y-x)xxN`
Here `(y-x)` is the volume of HCl
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