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Equivalent weight of a metal chloride is...

Equivalent weight of a metal chloride is 75.5. How many moles of NaOH is required to completely precipitate one mole of metal hydroxide. Atomic weight of the metal is 120.

Text Solution

Verified by Experts

The correct Answer is:
3
EQ of metal chloride = EQ wt of metal + EQ wt of `Cl^(-)`
75.5 = E + 35.5
E = 40
Valency = `(120)/(40)=3`
`therefore` Formula of metal chloride = `MCl_(3)`
`MCl_(3)+3NaOHrarrM(OH)_(3)darr+3NaCl`
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