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The density of water is 1g/mL. Assuming ...

The density of water is 1g/mL. Assuming that there are no intermolecular spaces between water molecules in liquid water, the volume of a water molecule is

A

`1.5xx10^(-23)ml`

B

`6xx10^(-23)ml`

C

`3xx10^(-23)ml`

D

`3xx10^(-22)ml`

Text Solution

Verified by Experts

The correct Answer is:
C

`6.023xx10^(23)` molecules water - 18 g
1 molecules water - `(1xx18)/(6.023xx10^(23))g`
1g water = 1 mL water
`(1xx18)/(6.023xx10^(23))g` water
`r=(1xx18)/(6.023xx10^(23))xx(1)/(1)~~3xx10^(-23)ml`
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