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We have 1.6 g CH(4),1.7gNH(3)and1.8gH(2)...

We have 1.6 g `CH_(4),1.7gNH_(3)and1.8gH_(2)O` select correct the alternate(s).

A

There are equal number of moles of each reactant

B

Total number of atoms in `CH_(4)gtNH_(3)gtH_(2)O`

C

Total number of H-atoms are in the ratio of `4:3:2`

D

Total number of C-atoms in `CH_(4)lt` that of N-atoms in `NH_(3)lt` that of O-atoms in `H_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

moles = `(1.6)/(10),(1.7)/(17),(1.8)/(18)`
atoms = `0.1N_(0)xx5,0.1N_(0)xx4,0.1N_(0)xx3`
H-atoms = `0.1N_(0)xx4,0.1N_(0)xx3,0.1N_(0)xx2`
no. of `C=N=O`
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