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10^(21) molecules are removed from 440mg...

`10^(21)` molecules are removed from 440mg of `CO_(2)`. It becomes

A

366mg

B

8.3 milli mole

C

200 mg

D

4.1 milli mole

Text Solution

Verified by Experts

The correct Answer is:
A, B
`10^(21)` molecules `(0.01)/(6)` moles = 73.3 mg
440mg = 0.01 moles
`therefore` left over = `0.01-(0.0.1)/(6)` moles = 8.3 moles
`=440-73.3mg =366.7mg`
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