Avogadro's lasw states that under conditions of constant temp. and pressure equal volume of gases contain equal no. of particles. Experimental investigation shows that at one atmosphere pressure and a temperature of 273 k, one mole of any gas occupies a volume of which is very close to 22.4 lit. Therefore, the number of moles in any gas sample canbe found by comparing its volume at STP with 22.4 lit.
If avagadro's number is `6xx10^(23)` molecules then the mass of one atom of oxygen would be

Options

A. `(16)/(6.02)` amu
B. `6xx10^(-23)` amu
C. 16 amu
D. `16xx6.02` amu

Answer

C

Explanation

1 Mole of oxygen `-6.023xx10^(23)` molecules of oxygen
`2xx6.023xx10^(23)` atoms of oxygen molecular weight of oxygen = 32
`2xx6.023xx10^(23)` atom of oxygen - 32g
1atom of oxygen = `(1xx32)/(2xx6.023xx10^(23))g`
`=16xx1.66xx10^(-24)g=16` amu