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One mole of N(2) H(4) loses 10 moles of ...

One mole of `N_(2) H_(4)` loses 10 moles of electrons to form a new compound X . Assuming that all the nitrogen appears in the new compound , the oxidation state of nitrogen in X is (there is no change in the oxidation number of hydrogen)

A

`-1`

B

`-3`

C

`+3`

D

`+5`

Text Solution

Verified by Experts

The correct Answer is:
C
`1N_(2)H_(4)rarr10e^(-)+x`
`n-f=2xxDelta` ox.no = 5
ox.no. of N in `N_(2)H_(4)=-2`
`implies -2+5=+3` final ox.no
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