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The molar mass of a solute X in g mol^(-...

The molar mass of a solute X in g `mol^(-1)`, if its 1% solution is isotonic with a 5% solution of cane sugar (molar mass = `342 g mol^(-)`), is

A

iron content in haemoglobin is 0.35% by mass

B

1 mole of haemoglobin contains 56 g iron

C

1 mole of haemoglobin contains 224 g iron

D

if iron content is increased to 0.56%, molar mass of haemoglobin would be higher than 65000 g `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`%Fe=(4xx56)/(65000)xx100=0.35%`
weight Fe in 1 mole = `4xx56=224g`
if % Fe `uarr`, m. wt `uarr`
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