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3Cl(2)+6NaOHrarr5NaCl+NaClO(3)+3H(2)O, c...

`3Cl_(2)+6NaOHrarr5NaCl+NaClO_(3)+3H_(2)O`, chlorine gets 

A

`(5)/(6)th Cl_(2)` content undergoes reduction

B

`(1)/(6)thCl_(2)` content undergoes reduction

C

The equivalent weight of chlorine molecule is 42.6

D

Equivalent weight of oxidised part of chlorine atom is 7.1

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
Out of 6Cl atoms, 5 get reduced 1 gets oxidized.
`E=E_("red")+E_("ox")=(71)/(2)+(71)/(10)=35.5+7.1=42.6`
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