Euivalent weights of two oxides of an element are 14 and 11 respectively. What is the ratio of atomicity of oxygen in the second oxide to first oxide?

Answer

2

Explanation

`E_(1)+8=14,E_(2)+8=11impliesE_(1)=6,E_(2)=3`
`A=6x,A=3yimplies(y)/(x)=2`