The amount of Mg in gms. to be dissolved...

The amount of Mg in gms. to be dissolved in dilute `H_(2)SO_(4)` to liberate `H_(2)` which is just sufficient to reduce 160g of ferric oxide is

A

24

B

48

C

72

D

96

Verified by Experts

The correct Answer is:

C

`Mg+H_(2)SO_(4)rarrMgSO_(4)+H_(2)`
`Fe_(2)O_(3)+3H_(2)rarr2Fe+3H_(2)O`
`160g-6g`
6gMg is given by 72g Mg

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