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If 0.5 mol of BaCl(2) is mixed with 0.2 ...

If 0.5 mol of `BaCl_(2)` is mixed with 0.2 mol of `Na_(3)PO_(4)` the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed is

A

`0.7`

B

`0.5`

C

`0.30`

D

`0.10`

Text Solution

Verified by Experts

The correct Answer is:
D
`3BaCl_(2)+2Na_(3)PO_(4)rarrBa_(3)(PO_(4))+6NaCl`
`(0.5)/(3)gt(0.2)/(2)`
implies `Na_(3)PO_(4)` is LR
`2Na_(3)PO_(4)rarrBa_(3)(PO_(4))_(2)`
implies `0.2 rarr 0.1`
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