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0.8 mole of a mixture of CO and CO(2) re...

0.8 mole of a mixture of CO and `CO_(2)` requires exactly 40 g of NaOH in solution for complete conversion of all the `CO_(2)` into `Na_(2)CO_(3)`. How many more moles of NaOH would it require for conversion into `Na_(2)CO_(3)`. If the mixture is completely oxidised to `CO_(2)`?

A

`0.2`

B

`0.6`

C

1

D

`1.5`

Text Solution

Verified by Experts

The correct Answer is:
B
Let moles of `CO_(2)=x`
40g NaOH = 1 mole
`2NaOH+CO_(2)rarrNa_(2)CO_(3)+H_(2)O`
`2rarr1`
`1rarr1//2` mole
implies moles of `CO=0.8-0.5=0.3`
`CO+1//2O_(2)rarrCO_(2)`
implies total moles of `CO_(2)=0.8`
`therefore` NaOH required = `2xx0.8=1.6`
Extra moles = `1.6-1=0.6`
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