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The correct Answer is:
A-S; B-P; C-Q; D-R

Limiting reagent in
A) `H_(2)` implies Moles of `NH_(3)=(0.1xx2)/(3)`
`=6.67xx10^(-2)`
B) C implies Moles of `C_(2)H_(2)=((1//12))/(2)`
`=4.16xx10^(-2)`
C) C implies Moles of `CO_(2)=(1)/(2)`
`8.3xx10^(-12)`
D) `O_(2)` implies Moles of `H_(2)O=((1)/(32))xx2`
`=6.25xx10^(-12)`
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