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Mole fraction of solute in an aqueous so...

Mole fraction of solute in an aqueous solution of NaOH is 0.1. If the specific gravity of the solution is 1.4, th normality of the solution is

A

6.9

B

0.1

C

71.4

D

0.14

Text Solution

Verified by Experts

The correct Answer is:
A
If moles of NaOH = x
Moles of water = 9x
`w_(1)=40x,w_(2)=162x`
implies Weight of solution = 202x
`V_("soln")=(202x)/(1.4)mL,N=(x)/(V_("soln (L)"))=6.9N`
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