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Molefraction of I(2) in C(6)H(6) is 0.2....

Molefraction of `I_(2)` in `C_(6)H_(6)` is 0.2. The molality of `I_(2)` in `C_(6)H_(6)` is

A

`3.205m`

B

`9.615m`

C

`6.41m`

D

`1.062m`

Text Solution

Verified by Experts

The correct Answer is:
A
`(X_(1))/(X_(2))=(mM_(2))/(1000)implies(0.2)/(0.8)=mxx(78)/(1000)impliesm=3.205m`
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