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1.00 gm of a mixture having equal number...

1.00 gm of a mixture having equal number of moles of carbonates of two alkali metals required 44.4 ml of 0.5 N HCl for complete reaction. Atomic weight of one of the metals is 7.00
The number of moles of each metal carbonate in

A

74 and 60

B

134 and 160

C

160 and 60

D

74 and 106

Text Solution

Verified by Experts

The correct Answer is:
d
Weigth of `"carbonate"_(1)=0.0055xxM.wt`
`=0.0055xx74=0.4107`
Weight of `"carbonate"_(2)=1-0.4107=0.5893`
implies M.wt = `(0.5893)/(0.055)=106`
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