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100 ml, 1.5M Fe(NO(3))(3). 100 ml, 2M Fe...

100 ml, 1.5M `Fe(NO_(3))_(3)`. 100 ml, 2M `FeCl_(3)`, 100 ml 2M `Mg(NO_(3))_(2)` are mixed and 700 ml water is added. The molar concentration of total ions in the solution in ______M

Text Solution

Verified by Experts

The correct Answer is:
2

Total moles of ions from `Fe(NO_(3))_(3)`
`=0.1xx1.5xx4=0.6`
From `FeCl_(3)=0.1xx2xx4=0.8`
From `Mg(NO_(3))_(2)=0.1xx2xx3=0.6`
`therefore` Total moles of ions = 2
`therefore M=(2)/(1)=2M`
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