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How may moles of H(2)O(2) must be presen...

How may moles of `H_(2)O_(2)` must be present in 2L of its solution, such that 100 ml of the solution can liberate 3.2 grams of oxygen at `273^(@)C` and 0.5 atm pressure?

Text Solution

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The correct Answer is:
4
`PV=((W)/(M))RT`
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)),(0.5xx8960)/(546)=(1xxV_(2))/(273)`
`0.5xxV=(3.2)/(32)xx0.0821xx546`
`V_(2)=2240ml`
`V=8.96` litres = 8960 ml
`100ml H_(2)O_(2)_____2240 ml` oxygen at STP
`1mlH_(2)O_(2)______22.4ml` oxygen at STP
volume strength of `H_(2)O_(2)=22.4`
1 volume `H_(2)O_(2)=3.03g//L=(3.03" moles")/(34)//L`
22.4 volume `H_(2)O_(2)=(22.4xx3.03" moles")/(34)//L`
= 1.99 moles/L `~~` = 2moles/L
For 2 litres = 4 moles
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