Home
Class 11
CHEMISTRY
To a 25 ml H(2)O(2) solution, excess of ...

To a 25 ml `H_(2)O_(2)` solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. The volume strength of `H_(2)O_(2)` solution is

A

`1.344`

B

`0.672`

C

`2.688`

D

`0.896`

Text Solution

Verified by Experts

The correct Answer is:
A
Eq `H_(2)O_(2)` = Eq `I_(2)` = Eq `NA_(2)S_(2)O_(3)`
`(25)/(1000)xxN=(20xx0.3)/(1000)`
`N=(1.2)/(5)=0.24N=1.344V`
Promotional Banner

Similar Questions

Explore conceptually related problems

25 ml of H_(2)O_(2) solution was added to excess of acidified Kl solution. The iodine so liberated required 20 ml. of 1 N sodium thiosulphate solution. What is volume strength of H_(2)O_(2)

Calculate the volume strength of 1.7% H_(2)O_(2) solution.

50 ml of given H_(2)O_(2) solution is added to excess KI solution in acidic medium. The liberated I_(2) requires 20 ml of 0.04 M standard Hypo solution. The strength of given 250 m H_(2)O_(2) solution is

The mole fraction of solute in 20% aqueous H_(2)O_(2) solution is

20ml of hydrogen peroxide solution is added to excess of acidified KI solution. The iodine so liberated requires 20ml of 0.1M hypo solution. Calculate the molarity and percentage strength of H_2O_2 solution.

Some amount of ..20V.. H_(2)O_(2) is mixed with excess of acidifeid solution KI. The iodine so liberated required 200ml of 0.IN Na_(2)S_(2)O_3 for tritration. The volume of H_2O_2 solution is

50 ml of given H_(2)O_(2) solution is added to excess KI solution in acidic medium. The liberated I_(2) required 20 ml of 0.04 M standard Hypo solution. Weight of H_(2)O_(2) present in 250 ml of given solution is