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X gm of KHC(2)O(4) requires 100 ml of 0....

X gm of `KHC_(2)O_(4)` requires 100 ml of `0.02 M KMnO_(4)` in acidic medium. In another experiment, y gm of `KHC_(2)O_(4)` requires 100 mkl of 0.05 M `Ca(OH)_(2)`. The ratio of x and y is

A

`1:1`

B

`1:2`

C

`2:1`

D

`5:4`

Text Solution

Verified by Experts

The correct Answer is:
B
Eqts of `KHC_(2)O_(4)` = Eq of `KMnO_(4)`
`(x)/((MW)/(2))=(100xx0.02xx5)/(1000)" ......."(1)`
Eqts of `KHC_(2)O_(4)` = Eq of `Ca(OH)_(2)`
`(y)/(MW)=(100xx0.05xx2)/(1000)" "......(2)`
from `(1), (2)(2x)/(y)=1" "x:y=1:2`
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