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Density of a 2.05 M solution of acetic ...

Density of a 2.05 M solution of acetic acid in water is 1.02 gm `ml^(-1)`. The molality of the solution is

A

`1.14molkg^(-1)`

B

`3.28molkg^(-1)`

C

`2.28molkg^(-1)`

D

`0.44molkg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`m=(1000M)/(1000d-MM_(1))=(1000xx2.05)/(1000xx1.02-2.05xx60)`
`=(2050)/(1020-123)=2.28" mol/kg"`
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