Home
Class 11
CHEMISTRY
Number of atoms of iron present in 100 g...

Number of atoms of iron present in 100 gm `Fe_(2)O_(3)` having 20% purity is

A

`0.2N_(A)`

B

`0.25N_(A)`

C

`0.5N_(A)`

D

`0.3N_(A)`

Text Solution

Verified by Experts

The correct Answer is:
B
No. of mole of pure `Fe_(2)O_(3)=(20)/(160)`
No. of Fe atoms = `(20)/(100)xx2xxN_(A)=0.25N_(A)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The number of atoms of hydrogen present in 1.5 mole of H_(2)O is

The number of d-electrons present in Fe^(2+) ion is

Calculate the oxidation number of iron in Fe_(3)O_(4) ?

The equivalent mass of iron in Fe_(2)O_3 would be

The number of Oxygen atoms present around Nitrogen in N_(2)O_(5) is

The oxidation number of iron in Fe+(2)(CO)_(9) is

Thermite is a mixture of Fe_(2)O_(3) and

The number of bridge oxygen atoms present in both P_(4)O_(6) and P_(4)O_(10) are respectively

The approximate mass of H_(2)O_(2) present in 200mL of 100 volume H_(2)O_(2) solution is

In the preparation of Iron from haematite (Fe_(2)O_(3)) by the reaction with carbon Fe_(2)O_(3)+CrarrFe+CO_(2) 94.5 kg of 10x% pure Iron could be produced from 120 kg of 90% pure Fe_(2)O_(3) ? Find the value of x.