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A sample of H(2)O(2) is x % by mass. If ...

A sample of `H_(2)O_(2)` is x % by mass. If x ml of `KMnO_(4)` are required to oxidize 1 gm of this `H_(2)O_(2)` sample, calculate the normality of `KMnO_(4)` solution.

A

`0.46N`

B

`0.5N`

C

`0.6N`

D

`0.65N`

Text Solution

Verified by Experts

The correct Answer is:
C
Let mass of `H_(2)O_(2)` solution = 100 gm
mass of `H_(2)O_(2)` present is = xgm
given that mass of `H_(2)O_(2)` solution taken = 1 gm,
So, mass of `H_(2)O_(2)` present in 1 gm solution
`=(x)/(100)` Eq. of `H_(2)O_(2)=(x)/(100xx(34//2))`
Eq. of `KMnO_(4)=NxxV(C)=Nxx x xx10^(-3)`
Now `(x)/(100xx17)=Nxx x xx10^(-3)impliesN=0.59N`
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