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50 ml solution of H(2)O(2) was treated w...

50 ml solution of `H_(2)O_(2)` was treated with excess KI (s) and the solution was acidified with acetic acid. The liberated `I_(2)` required 40 ml of `0.5 M Na_(2)S_(2)O_(3)` solution for the end point using starch is indicator. Find the molairty and volume strength of the `H_(2)O_(2)` solution.

A

1.12 gm lit

B

2.24 gm/lit

C

5.6 gm/lit

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
Meq of `H_(2)O_(2)` M 50 ml
= m.eq of Hypo = `40xx0.5=20` meq
Now normality = `(20)/(50)=0.4N`
`implies M=0.2M`
`therefore` Volume strength = `Mxx11.2=0.2xx112=2.24gm//lit.`
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