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When 4 gm of Mg burnt with O(2) form oxi...

When 4 gm of Mg burnt with `O_(2)` form oxide and on dilution of metal oxide form metal hydroxide which statement is/are correct for above series of reaction?

A

Gram equivalent of metal, metal oxide an metal hydroxide are equal

B

Weight of metal oxide is 6.66 gm

C

Weight of metal hydroxide is 9.66 gm

D

Normality of solution in 1 litre volume is `(14)/(42)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`2Mg+O_(2)rarr2MgO`
`MgO+H_(2)OrarrMg(OH)_(2)`
Eq. of Mg = Eq. of Mgo = Eq. of `Mg(OH)_(2)`
`(4)/(12)=(W)/(20)impliesW=6.66gm`
`therefore` Eq of MgO = 6.66
Eq. of Mg = Eq. of `Mg(OH)_(2)`
`(4)/(12)=(w)/(29)impliesW=(29)/(3)=9.66gm`
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