Choose the correct match.

Options

A. `18mlH_(2)O` at `4^(@)C` contains `6.023xx10^(24)` electrons
B. 11200 ml of `CO_(2)` at STP contains `6.023xx10^(23)` oxygen atoms.
C. 5600ml of `CH_(4)` at 273 K and 2 atm contains `12.04xx10^(23)` hydrogen atom.
D. 5600 ml of `CH_(4)` at STP contains `1.505xx10^(23)` methane molecules.

Answer

A, B, C, D

Explanation

a) 18 ml implies 18 gm = 1 mole = 10 moles of `e^(-)`
b) 11200 ml = 0.5 moles of `CO_(2)`
= 1 moles of O atoms
c) 5600 ml at 2 atm implies 11200 at 1 atm
= 0.5 moles of `CH_(4)=4xx0.5`
= 2 moles of H atoms
d) 5600 ml at STP implies 0.25 moles of `CH_(4)` molecules