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A sample of crystalline Ba(OH)(2). XH(2)...

A sample of crystalline `Ba(OH)_(2). XH_(2)O` weight 1.578 gm was dissolved in water. The solution required 40 ml of `0.25 N HNO_(3)` for complete relation. Determine the number of molecular of water of crystallisat in base.

Text Solution

Verified by Experts

The correct Answer is:
8
Eqts of `Ba(OH)_(2).xH_(2)O` = Eq of `HNO_(3)`
`(1.578)/((171+18x)//2)=(40)/(1000)xx0.25`
`18x=315.6-171impliesx=8`
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