Home
Class 11
CHEMISTRY
How may gram of 83.4% pure sodium sulpha...

How may gram of 83.4% pure sodium sulphate can be produced form 250 g of 95% pure NaCl.

A

`288.2g`

B

`237.5g`

C

`345.4g`

D

`187.2g`

Text Solution

Verified by Experts

The correct Answer is:
C

`2NaCl+H_(4)SO_(4)rarrNa_(2)SO_(4)+2HCl`
Amount of pure `NaCl=250xx(95)/(100)=237.5g`
`2xx58.5gNaCl-142gNa_(2)SO_(4)`
`237.5gNaCl-288.2gNa_(2)SO_(4)`
To get 83.4 pure `Na_(2)SO_(4)` - take 100g impure sample of `Na_(2)SO_(4)`
To get 288.2g pure `Na_(2)SO_(4)` - take 345.4g impure `Na_(2)SO_(4)`
Promotional Banner

Similar Questions

Explore conceptually related problems

In the preparation of Iron from haematite (Fe_(2)O_(3)) by the reaction with carbon Fe_(2)O_(3)+CrarrFe+CO_(2) 94.5 kg of 10x% pure Iron could be produced from 120 kg of 90% pure Fe_(2)O_(3) ? Find the value of x.

How many grams of 40% pure sodium hydroxide is dissolved in 0.5 M, 250 ml NaOH solution?

How many grams of 80% pure marble stone on calcination can give 14 grams of quick lime?

A certain weight of sodium Iodine and sodium chloride mixture when treated with sulphuric acid was found to give the same weight (as that of mixture) of sodium sulphate. The percentage composition of NaCl is

How many grams of H_(2)SO_(4) required to be dissolved in 250g of water to prepare decimolal solution?

The volume of CO_(2) that can be obtaind at STP from 60 g. of 70% pure MgCO_(3) is

An isotonic solution will produce an osmotic pressure of 10.00 atm measured against pure water at 37^@C . How many grams of NaCl must be dissolved in one litre of water to produce at isotonic solution