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On gram of the carbonate of a metal was ...

On gram of the carbonate of a metal was dissolve din 35 CC 1N HCl.The resulting liquid required 50 CC `N/10` caustic soda solution to neutralise it completely. The equivalent weight of metal carbonate is

A

100

B

25

C

53

D

50

Text Solution

Verified by Experts

The correct Answer is:
D
`"50CC of "(N)/(10)NaOH="50CC of "(N)/(10)HCl`
`=5C C 1NHCl`
Volume of acid left = `5C C 1NHCl`
Volume of acid used by metal carbonate
= `25.5 = 20C C 1 NHCl`
No. of MeQ of `HCl=20xx1=20`
No. of meQ of metal carbonate
= `(1)/("GEW of M.C")xxoverset("1 ")(1000)`
No. of mecq of HCl = No. of mecq of metal carbonate
`20=(1)/("GSW of M.C.")xx100`
GtW of M.C = 50 `therefore` EQ wt of M.C. = 50
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