The correct statements are

Options

A. The isotopes of chlorine with mass number 35 and 37 exist in ratio `3:21` if its average atomic mass is 35.5
B. The mass of one amu is approximately `1.6xx10^(-24)g`
C. The number of molecules in 1 ml of a gas at STP is called Loschmidt number
D. If `6.023xx10^(21)` molecules of a solute are present in 100 ml solution molarity of solution is 0.1M

Answer

A, B, C

Explanation

a) `35.5=(75xx35+25xx37)/(100)`
d) Molarity = `("No. of molecules of solute")/(6.023xx10^(23))xx(1000)/("volume of solution in ml")`
Molarity = `(6.023xx10^(21))/(6.023xx10^(23))xx(1000)/(10)=0.1M`