Home
Class 11
CHEMISTRY
Two formulal to calculate number of mill...

Two formulal to calculate number of milli equivalents (mlQ)
Numbr of miliequivalents `=("weight")/("GEW")xx1000`
Numbr of milliequivalents= volume in ml `xx` Normality of solution
0.25 grams of pure `CaCO_(3)` neutralised 25 ml dilue HCl normality of HCl solution is

A

0.1 N

B

0.5 N

C

0.25 N

D

0.2 N

Text Solution

Verified by Experts

The correct Answer is:
D
No. of Meq of `CaCO_(3)=(0.25)/(50)xx1000`
No. of Meq of HCl = `25xx` Normality of the solution
No. of Meq of `CaCO_(3)` = No. of Meq of HCl
`therefore` Normality of HCl solution = 0.2N
Promotional Banner

Similar Questions

Explore conceptually related problems

Two formulal to calculate number of milli equivalkents (mlQ) Numbr of miliequivalents =("weight")/("GEW")xx1000 Numbr of milliequivalents= volume in ml xx Normality of solution 0.09 grams of dibasic acid neutralise 40 ml of N/20 NaOH solution. Molecular weight of acid is

The volume of 0.1 M HCl required in mL to neutralise 20 mL of a solution containing 0.106 g of Na_(2)CO_(3) is

20. ml of 0.2 N HCl and 40 ml of 0.4 N HNO_3 are mixed and the solution is diluted up to 100 ml. Calculate the normality of the soluton. ?

5 ml of 1N HCl, 20 ml of N/2 H_2SO_4 and 30 ml of N/3 HNO_3 are mixed together and the volume made to one litre. The normality of the resulting solution is

The pH of the mixture of 25 ml of 0.01 M of CH_3 COOH (K_a of CH_3 COOH = 5 xx 10 ^(-5) ) and 25 ml of 0.01 M of NaOH solution is

NaOH and Na_(2)CO_(3) are dissolved in 200ml aqueous solution. Now methyl orange is added in the same solution titrated and requires 2.5ml of the same HCl. Calculate the normality of NaOH & NaCO_(3) .