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{:("Column-I","Column-II"),("A) 22.4 vol...

`{:("Column-I","Column-II"),("A) 22.4 volume "H_(2)O_(2),"P) 11.2 litres"),("B) 32 g oxygen","Q) "9.034xx10^(23)" atoms"),("C) 11.2 L "CO_(2)" at STP","R) 2 mole"L^(-1)),("D) 1 gram equivalent hydrogen at STP","S) "9.64xx10^(24)" electron"):}`

Text Solution

Verified by Experts

The correct Answer is:
A-R; B-S; C-Q; D-P
A) 1 vol `H_(2)O_(2)=3.03g//L`
22.4bol `H_(2)O_(2)=22.4xx3.03=67.87g//L`
`=~~2" moles/L"`
B) 32 g oxygen = 1 mole oxygen
= `6.023xx10^(23)` molecules
`=6.023xx10^(23)xx16=9.64xx10^(24)` electrons
C) 11.2L `CO_(2)` at STP
`=(1)/(2)` mole `CO_(2)=(1)/(2)xx6.023xx10^(23)` molecules
`=(1)/(2)xx6.023xx10^(23)xx3` atom
`=9.034xx10^(23)` atom
D) 1 gram equivalent hydrogen
= 1 g hydrogen
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