BeCI(2)+LiAIH(4)rarrX-LiCI +AICI(3)...

`BeCI_(2)+LiAIH_(4)rarrX-LiCI +AICI_(3)`

X is LiH

X is `BeH_(2)`

X is `BeCI_(2)2H_(2)O`

None

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The correct Answer is:

`2BeCi_(2) + LiAIH_(4) rarr 2BeH_(2) + LICI + AICI_(3)`

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