A closed organ pipe of length L and an open organ pipe contain gases of densities `rho_(1) and rho_(2)` respectively. The compressibility of gases are equal in both the pipes. Both the pipes are vibrating in their first overtone with same frequency. The length of the open pipe is `(x)/(3)L sqrt((rho_(1))/(rho_(2)))` where x is ...... (Round off to the Nearest Integer)

A closed organ pipe of length L and an open organ pipe contain gases of densities rho_1 and rho_2 resp. The compressiblity of gases are equal in both pipes. Both pipes are vibrating in first overtones with same frequency. The length of open organ pipe is

A closed organ pipe of length L and an open organ pipe contain gass of densities rho_(1) and rho_(2) , respectively. The compressibility of gass are equal in both the pipes. Both the pipes are vibrating in their first overtone with same frequency . The length of the open orange pipe is (a) (L)/(3) (4l) / (3) (c ) (4l)/(3)sqrt((rho_(1))/(rho_(2))) (d) (4l)/(3)sqrt((rho_(2))/(rho_(1)))

In open organ pipe, first overtone produced is of such frequency that length of the pipe is equal to

The second overtone of an open pipe has the same frequency as the first overtone of a closed pipe 2 m long. The length of the open pipe is

if the first overtone of a closed pipe of length 50 cm has the same frequency as the first overtone of an open pipe, then the length of the open pipe is

The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L metre long. The length of the open pipe will be

Second overtone of a closed pipe of length , 1m is in unison with third overtone of an open pipe , then the length of the open pipe will be