Home
Class 12
PHYSICS
The velocity of a particle is v=v(0)+g t...

The velocity of a particle is `v=v_(0)+g t+Ft^(2)`. Its position is x=0 at t=0, then its displacement after time (t=1) is :

A

`v_(0)+(g)/(2)+(F)/(3)`

B

`v_(0)+2g+3F`

C

`v_(0)+(g)/(2)+F`

D

`v_(0)+g+F`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

The velocity of a particle is v=v_(0)+gt+ft^(2) .If its position is x=0 at t=0, then its displacement after 1s is

The velocity of particle is v=v_(0)+"gt"+ft^(2) . If its position is x=0 at t=0 then its displacement after unit time (t=1) is

The velocity of a particle is v = v_(0) + gt + ft^(2) . If its position is x=0 at t= 0 , then its displacement after unit time ( t = 1 ) is

The velocity of a particle is v = v_0 + g t + ft^2 . If its position is x = 0 at t = 0 , then its displacement after unit time (t = 1) is.

The velocity of a particle is given by v=u_(0) + g t+ 1/2 at^(2) . If its position is x =0 at t=0 , then what is its displacement after t=1 s ?

If velocity of a particle is given by v=3t^(2)-6t +4 . Find its displacement from t=0 to 3 secs .

If velocity of a moving particle in is v= a + g t + ft^2 (a,g,f are constants). At t=0 body is at origin. Find displacement after t=1s.

The acceleration of a particle is given by a = 3t and at t = 0, v = 0, x = 0. The velocity and displacement at t = 2 sec will be-

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

Velocity-time equation of a particle moving in a straight line is, v=(10+2t+3t^2) (SI units) Find (a) displacement of particle from the mean position at time t=1s, if it is given that displacement is 20m at time t=0 . (b) acceleration-time equation.