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KBr is doped with 10^(-5) mole percent ...

KBr is doped with `10^(-5)` mole percent of `SrBr_(2)`. The number of cationic vacancies in 1 g of KBr crystal is ________`10^(14)`. (Round off to the Nearest Integer).
[Atomic Mass : K : 39.1 u, Br : 79.9 u `N_(A)=6.023 xx 10^(23)`]

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