Answer
Step by step text solution for Expand the expressions given below:- (1 - 2x)^5 by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.
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PSEB-BINOMIAL THEOREM-EXERCISE
- Expand the expressions given below:- (1 - 2x)^5
06:03
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- Expand the expressions given below:- (2/x-x/2)^5
08:00
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- Expand the expressions given below:- (2x -3)^6
08:18
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- Expand the expressions given below:- (x/3 + 1/x)^5
07:18
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- Expand the expressions given below:- (x+1/x)^6
06:24
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- Using binomial theorem, evaluate the following: (96)^3
05:25
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- Using binomial theorem, evaluate the following: (102)^5
07:35
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- Using binomial theorem, evaluate the following: (101)^4
06:35
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- Using binomial theorem, evaluate the following: (99)^5
06:44
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- Using Binomial Theorem, indicate which number is larger (1.1)^10000 or...
06:01
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- Find (a + b)^4 -(a -b)^4 . Hence, evaluate (sqrt3+sqrt2)^4-(sqrt3-sqrt...
07:49
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- Find (x + 1)^6 + (x -1)^6. Hence or otherwise evaluate (sqrt2+1)^6 + (...
07:36
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- Show that 9^(n+1) -8n -9 is divisible by 64, whenever n is a positive ...
11:30
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- Prove that sum(r=0)^n 3^r "^nCr= 4^n.
02:25
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- Find the coefficient of x^5 in (x + 3)^8
05:23
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- Find the coefficient of a^5 b^7 in (a - 2b)^12 .
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- Write the general term in the expansion of (x^2 - y)^6
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- Write the general term in the expansion of (x^2 - yx)^12 , x ne 0.
02:31
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- Find the 4th term in the expansion of (x-2y)^12.
04:03
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- Find the 13th term in the expansion of (9x-1/(3sqrtx))^18, x ne 0.
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