How to find Bond Order of Homolecular Diatomic Species ?

Find the bond order of CO

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Q and R are homonuclear diatomic species and have their bond order 2.4, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. The correct statement is :

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. The incorrect statements is :

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. According to given information the incorrect match is :

The corrent bond order in the following species is