If `absA` = m , `absB` = n ,what can you say about `abs(P(A) X P(B))`

Explanation

If `absA` = m , `absB` = n then `absP(A) = 2^m . absP(B) = 2^n therefore absP(A) xx P(B) = 2^m xx 2^n = 2^(m+n)`