Solve as directed: 5x + 7 `lt` 32 in integers, in non-negative integers.

Explanation

5x + 7 `lt` 32
`rArr 5x+7-7 lt 32-7`
`rArr 5x lt 25`
`rArr (5x)/5 lt (25)/5`
`rArr x lt 5`
If x `in` Z then the solution set is S = {x:x `in` Z and x `lt` 5}
={……. -3,-2,-1,0,1,2,3,4} If x is a non negative solution then the solution set is
S = { x: x is a non negative integer `lt` 5} = {0,1,2,3,4}