Solve as directed : x/2 + 7/2 `lt` 3x-1 in R

Explanation

x/2 + 7/2 `lt` 3x-1
`rArr (3x + 14)/6 lt (3x-1)`
`rArr 3x + 14 lt 18x - 6`
`rArr 3x -18x lt -6 -14`
`rArr -15x lt -20
`rArr (-15x)/(-15) gt (-20)/(-15)`
`rArr x gt 4/3`
If x `in` R , the solution set is S = (4/3 , `infty`) = {x:x `in` R and x`gt` 4/3}