Solve as directed : x/2 - x/3 + x/5 `le` 11/3 for non-negative real numbers.

Explanation

x/2 - x/3 + x/5 `le` 11/3
`rArr (15x-10x-6x)/30 le 11/3`
`rArr 11x le (11/3) xx 30`
`rArr 11x le 110
`rArr x le 10
If x is a non negative real number then the solution set is
S = {x:x `in` R and `0 le x le 10`}
= {0, 10 }