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Find n"if" P (n,4)=12.P(n,2)...

Find `n"if" P (n,4)=12.P(n,2)`

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`""^nP_4=12xx""^nP_2`
` or,(n!)/((n-4)!)=12xx(n!)/((n-2)!)`
`or, (n-2)! =12(n-4)!`
`or,(n-2)(n-3)(n-4)! =12(n-4)!`
`or,(n-2)(n-3)=12`
`or,n^2-5n-6=60`
`(n-6)(n+1)=0`
`or, n=6-1`
Hence `n=6` as n is a natural number.
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MBD PUBLICATION-PERMUTATIONS AND COMBINATIONS-QUESTION BANK
  1. Show that 2.6.10…….to n factors =((2n)!)/(n!)

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  2. Find r if P (20,r)=13.P(20,r-1).

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  3. Find n"if" P (n,4)=12.P(n,2)

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  4. IfP(n-1,3):P(n+1,3)=5:12,"Find "n.

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  5. Find m and n if P(m+n,2)=56,P(m-n,2)=12

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  6. Show that P(n,n)=P(n,n-1)"For all positive integers."

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  7. Show that P(m,1)+P (n,1)=P(M+n,1)for all positive integers m, n.

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