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Apply Binomial Theorem to find the value...

Apply Binomial Theorem to find the value of `(1.01)^5`

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`(1.01)^5` = `(1+0.01)^5`
`1+^5C_1(0.01)^1+^5C_2(0.01)^2 + ^5C_3(0.01)^3 + ^5C_4(0.01)^4 + (0.01)^5`
= `1+5xx0.01+10(0.0001) + 10(0.000001) + 5(0.00000001) + 0.0000000001
1+0.05+0.001+0.00001+0.00000005+0.000000001
1.0510100501
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