Obtain the equation of straight lines : Whose perpendicular distance from origin is 2 such that the perpendicular from origin has indication 150.

Explanation

Equation of the line in normal form is `xcosalpha + ysinalpha = p`
or, `xcos150^@ + ysin150^@ = 2
or, `-xsqrt3/2 + y.1/2 = 2`
or, `-xsqrt3 + y = 4`
or, `xsqrt3 - y + 4 = 0`