Find the equation of circles determined by the following conditions. The centre at (3, 2) and circle is tangent to x-axis.

Explanation

`therefore` Radius = 2
`therefore` Eqn. of the circle is
`(x-h)^2 + (y-k)^2 = a^2`
or, `(x-3)^2 + (y-2)^2 = 4`
or, `x^2 + 9 - 6x + y^2 + 4 - 4y = 4`
`x^2 + y^2 - 6x - 4y + 9 = 0`