Find the length of the tangent, drawn to the circles `x^2+y^2+10x-6y+8=0` from the centre of the circle `x^2+y^2-4x=0`

Explanation

Centre of the circle
`x^2+y^2-4x=0` is (2, 0).
`therefore` Length of the tangent drawn from the point (2, 0) to the circle
`x^2+y^2+10x-6y+8=0` is
`sqrt(x_1^2+y_1^2+2gx_1+2fy_1+c)`
= `sqrt(4+0+10xx2+0+8)=sqrt(32)=4sqrt2`