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Find the length of the tangent drawn fro...

Find the length of the tangent drawn from the point (2, -1) to the circle `x^2+y^2-6x+ 10y+18=0`.

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Length of the tangent drawn from the point (2, -1) to the circle
`x^2+y^2-6x+10y+18=0` is
`sqrt(x_1^2+y_1^2+2gx_1+2fy_1+c)`
= `sqrt(4+1+(-6)xx2+10(-1)+18)`
= `sqrt(5-12-10+18)` = 1.
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MBD PUBLICATION-CONIC SECTIONS-QUESTION BANK
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