Find the equation of the parabola in each of the following cases:vertex at (1,-1) and the directrix y-2=0

Explanation

vertex at (2,-1) directrix y-2=0 `therefore` h=1,k=-1 We have directrix is y=k-a `therefore a=-3` `therefore` eqn of the parabola is
` (x-h)^2=4a(y-k) implies (x-1)^2+12(y+1)=0`